Tips from the pros video

Our tips from the pros video! 

http://www.youtube.com/watch?v=AgE-e9Z-6rE

Unit 1 - Day 8:

Day 8

Daily Objective: students will know what scale factor of sides and scale factor of area is

Scale factor is used to figure out the size or area of something using other smaller objects that are excatly the same but a different size. Its a more logic way to find area and lengths then to measure out the whole thing. 

Quiz : 

Question 1: Find x

Question 2: What is the length CB if FE is 3cm ? 

Question 3: What is the scale factor?

Quiz: Answers : 

Question 1. Find x :

       1.) set the equation up.

       2.)  X  = 7

            23    14

       3.) 14 x = 161

       4.) 161/14 = 11.5

Answer: x = 11.5 ( the ratio is 1:2) 

Question 2. What is the length CB if FE is 3cm ? 

       1.) Set the equation up.

       2.)  8  =  X 

             2      3

       3.) 2x = 8x3 which is 24

       4.) 24 / 2 = 12

Answer: CB = 12 cm 

Question 3. What is the scale factor?

 The scale factor is 1:4

Unit 1 - Day 7:

Day 7:

Daily Objective: Students will know what similar triangles are.

Triangles are similar if they have the same shape but are different sizes.

In order to be able to find the area or one side of the trianlge you need to have a similar triangle to compare it to and use its ratio.

video: http://www.youtube.com/watch?v=gQoNjgayoLI

In order to find x you need to use the similar triangles and put them into a ratio/ use cross multiplication. The equation would be set up like this ..  9  =  X 

                                                                                                        4      2 

So 4x = 9x2 which is 18. 18/4 = 4.5 the ratio is 1:2

Quiz :

Quiz : Answers:

Question 1: These figures are similar. The area of triangle ABC is 850 square ft. Find the area of triangle DEF.

       1.) Set up the equation :    30   =   40  

                                              850        X

       2.) Cross multiply these numbers. 

       3.) New equation : 30x = 830 x 40 which is 34000

       4.) 34000 / 30 = 1133.33 

Answer : 1133.33 ft squared

Question 2: Find the area of the small figure given. The area of the large is 72 square inches. The triangle are similar.

       1.) Set up the equation :  6  =  12 

                                             X     72      

       2.) Cross multiply these numbers.

       3.) New equation : 12x = 72 x 6 which is 432

       4.) 436/12 = 36

Answer : 36 in. squared

Question 3: Find the value of X if the triangles are similar

       1.) Set up the equation :  6  =  4 

                                            12     x

       2.) Cross multiply these numbers.

       3.) New equation : 6x = 12 x 4 which is 48

       4.) 48 / 6 = 8 .

Answer: 8 un. squared

                    

Unit 1 - Day 6:

Day 6 :

Daily Objective: Students will learn similar triangles and learn angle-angle. 

Angle - Angle Similarity :

Two triangles that are similar is two angles of a triangle are congruent to two angles of another triangle That would mean that the triangle ABC and DEF are similar on both of these figures.

Quiz :

Quiz 6: Answers

1.) Yes because it is just the same shape , different size and same angles.

2.) No because it is the same shape, different size but different angles.

3.) Yes because it is the same shape, different size and same angles.

Unit 1 - Day 5:

Day 5:

Daily Objective: Students know similar figures and find missing lengths from them. 

Similar figures: Similar figures are two figures that have the same shape but can be a different size. When two figures are similar, the ratios of their lengths corresponding sides are equal.

In order to find the missing sides you need to set it up in a proportion, by using the X method. So this example the problem would look like this:

    6  =  X 

   10    5

Once you have this equation down you need to cross multiply the numbers so the equation would be 6x5 = 10x so 10x = 30. 30 divided by 10 is 3. Therefor x = 3. So the length of that side of the trangle is 3.

In these similar figures answer these questions:

Does AB = DE? 

Does AC = DF? 

How do you set the equation up?

Yes AB = DA , Yes AC = DF 

The equation is AB over AC and DA over DF. 

Quiz :

Quiz : Answers :

Question 1 : Find the length of x. 

       1.) Set the equation up ; 50 = 7

                                              x      7

       2.) Now you need to cross multiply 7x = 50 x 7

       3.) 50 x 7 = 350 and now you need x alone so 350 divided by 7 = 50

       4.) So the length of x is 50

Answer: 50 units

Question 2 : The two rectangles are similar. The ratio of their areas is 9:16 find the missing side. 

       1.) Set the equation up :  9   =  20 

                                             16        x

       2.) Now cross multiply : 9x = 20 x 16.

       3.) 20 x 16 = 320 

       4.) 320 / 9 = 35.5, so X = 35.5

       5.) So X is 35.5 , the missing length is 35.5 

Answer: 35.5 units

Question 3 : Find the area of the trapezoid.
       1.) Use the formula B1 + B2 x H
                                            2
       2.) Plug in the numbers to the formula : 10 + 20 x 5
                                                                           2
       3.) 10 + 20 = 30 /2 = 15
       4.) 15 x 5 = 60.
       5.) The area will be 60 units

Answer: 60 units 

Unit 1 - Day 4:

Day 4:

Daily Objective : Students will know how to find the surface area of a prism, pyramid, cylinder, cone, and sphere; they will know the real life meaning to finding the surface area of these figures. 

Surface area is the area that is only the shape of the surface; nothing inside of the figure.
Surface area is used for many different things. You can use surface area to be able to build a house or paint a house.

Formulas:
Prism - Area of bases  + Area of sides
Pyramid - b x h /2 if its a polygon pyramid - b x h/2 + 1/2 a x perimeter
Cylinder -2(pi x radius squared) + 2 (pi x d x h)
Cone - pi x radius squared + pi x r x L (slant height)
Sphere - 4 x pi x radius squared , the area of four circles

Videos to explain each :
Prism - http://www.youtube.com/watch?v=Pcjnz26pnwY
Pyramid - http://www.youtube.com/watch?v=MV9tue_6q0c
Cylinder - http://www.youtube.com/watch?v=gi7aaZ87EoQ
Cone - http://www.youtube.com/watch?v=UyesG4M7jBo
Sphere - http://www.youtube.com/watch?v=FmngB6YnqP4

Quiz 4: 

Quiz 4 :  Answers :

Question 1. Find the area of the circle clock tower face if the circumference is 24pi units. 

       1.) 12 squared times pi 

       2.) 12 x 12 = 144 

       3.) 144 x pi ( 3. 14) = 452.38

Answer: 452.38 ft squared

Question 2. Find the surface area of the house ignore the floor

       1.) 10 + 18 / 2 x 8 = 164 

       2.) 82 x 2 = 164

       3.) 32 x 2

       4.) 10 x 8 = 80

       5.) 80 x 2 = 160

       6.) 18 x 10 =180

       7.) 180 x 2 = 360

       8.) 164 + 64 + 160 + 360  = 748 all the surfaces added together

Answer : 748 ft. squared

Question 3. Find a surface area of a igloo with a 20ft diameter

       1.) Find the radius, which is 10 x 10 = 100
       2.) 

    

Unit 1 - Day 3:

Day 3:

Daily Objective: Students will learn the surface area formulas for a pyramid, cylinder, cone, and sphere.

Formulas:
Prism - Area of bases  + Area of sides
Pyramid - b x h /2 if its a polygon pyramid - b x h/2 + 1/2 a x perimeter
Cylinder -2(pi x radius squared) + 2 (pi x d x h)
Cone - pi x radius squared + pi x r x L (slant height)
Sphere - 4 x pi x radius squared , the area of four circles

Surface area is the area ONLY covering the surface of the figure and nothing else. 

Quiz :

Quiz 3: Answers :

Question 1. Find the surface area
       1.) 15 x 15 = 225, which is the area of the base
       2.) 11 x 15/2 = 330 which is the area of sides
       3.) 330 x 3 = 990 which is area of ALL sides
\      4.) 990 + 225 = 1215 in. squared adding together the surface areas

Answer : 1215 in. squared

Question 2. Find the surface area
       1.) 5 x 5 = 25 area of the base
       2.) 5 x 25 = 125 area of sides
       3.) 25 x 2 = 50 which is both the sides
       4.) 125 x 4 = 500 which is all the sides added together
       5.) 500 + 50 = 550 adding together all the surface areas

Answer : 550 in. squared

Question 3. Find the surface area 

       1.) 15 x 11 = 165 which is the area of the sides

       2.) 165 x 3 = 495 which is the area of all the sides

       3.) 10 x 10 / 2 = 50 which is the area of the base

       4.) 50 x 2 = 100 which is the area of the bases combined

       5.) 495 + 100 = area of all the surfaces

Answer : 595 in. squared